|
Message
From: Marc Reinig<mreinig@p...>
Date: Tue Mar 9 16:38:54 CET 2004
Subject: [usb] USB1.1 transceiver
This is just describing a worst case of a pull down of the 1.5K resistor
from 3.3V + 10% = ~3.6V.
The point I was trying to make was that you must not source current when
Vbus of the host is removed. So if your device is plugged in and your
resistor is not gated by Vbus, it will source current to the host.
Marc Reinig
System Solutions
-----Original Message-----
From: usb-bounces@o... [mailto:usb-bounces@o...]On
Behalf Of M. AbuKhater
Sent: Tuesday, March 09, 2004 6:50 AM
To: Discussion list about free, open source USB IP core
Subject: RE: [usb] USB1.1 transceiver
as I saw in the USB2.0 Spesification ( 7.1.1) a pull up resistor should be
connected to a 3.6V to D+ so the host can detect it. about Vbus (the 5 V one
, am not using it at all),
did u mean it this way or did I got u wrong?
AbuKhater
Marc Reinig <mreinig@p...> wrote:
According to the USB spec., you are not supposed to source any current
when Vusb is not present. You need to gate your connection between the 3.3
V (J3 - 5) and R10 with Vusb.
Marc Reinig
System Solutions
-----Original Message-----
From: usb-bounces@o... [mailto:usb-bounces@o...]On
Behalf Of Mohhammad AK
Sent: Monday, March 08, 2004 10:34 AM
To: usb@o...
Subject: [usb] USB1.1 transceiver
hi everybody
I would appreciate, any comments on the attached schematic.
thanks
AbuKhater
--------------------------------------------------------------------------
Do you Yahoo!?
Yahoo! Search - Find what youre looking for faster.
_______________________________________________
attachment.htm
|
 |
Browse
