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    Navigation: All forums > Usb > Message List > Message Post

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    From: Madhusudhan Rao <madhu_sudhana_rao@y...>
    Date: Wed, 20 Feb 2002 15:48:41 -0800 (PST)
    Subject: Re: [usb] crc algorithm
    Top

    hai Tambunan,
        I am attaching the crc generation schematic. I
    hope
    it will clear ur remaining doubts.
    
    regards
    madhu
    
    
    --- RE Tambunan <kebloo@m...> wrote:
    > On 20 Feb 2002 at 11:10, Madhusudhan Rao wrote:
    > 
    > > HiTambunan,
    > >    G(x) = x^16+x^15+x^2+1 for  1000000000000101B.
    > >    G(x) = x^5+x^2+1 for  00101B.
    > > X^5 in the above expression will give u
    > information as
    > > you are using 5 bit crc. otherwise we will not
    > have
    > > any idea that how much crc polynomial length.
    > > I hope the above explanation is clear to u.
    > > If u still not clear i will send u an example code
    > for
    > > crc aslo.
    > Hello Madhu,
    > 
    > Thanks for the information. You are right about X^5
    > indicates using 5-bit CRC. Some on-line CRC document
    > I've already collected also said about that.
    > But...(CMIIW...)
    > it's just an indication of type of CRC used. Because
    > CRC (or remainder in CRC math calculation) will
    > always
    > no more than 5 bits. The question is why the
    > Generator
    > Polynomial (or divisor in CRC math calculation) 
    > also be
    > represented in 5 binary bits pattern not 6 bits ?...
    > 
    > I'm really thankfull if you could send me your
    > example
    > code of CRC, because it could help me understand
    > this
    > matter.
    > 
    > > 
    > > Best regards
    > > Madhu
    > > 
    > Best Regard,
    > 
    > 
    > RE Tambunan
    > 
    
    
    =====
    MadhusudhanaRao.M
    
    

    crc.pdf

    ReferenceAuthor
    Re: [usb] crc algorithmRE Tambunan

    Follow upAuthor
    Re: [usb] crc algorithmRE Tambunan

     
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